6/5+9/10(x-2)=11/5(x+3)

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Solution for 6/5+9/10(x-2)=11/5(x+3) equation: 



6/5+9/10(x-2)=11/5(x+3)

We move all terms to the left:

6/5+9/10(x-2)-(11/5(x+3))=0



Domain of the equation: 10(x-2)!=0

x∈R





Domain of the equation: 5(x+3))!=0

x∈R



We calculate fractions


(225xx/(10(x-2)*5(x+3))*5)+(-110xx/(10(x-2)*5(x+3))*5)+(60xx/(10(x-2)*5(x+3))*5)=0



We calculate terms in parentheses: +(225xx/(10(x-2)*5(x+3))*5), so:

225xx/(10(x-2)*5(x+3))*5

We multiply all the terms by the denominator


225xx

Back to the equation:

+(225xx)





We calculate terms in parentheses: +(-110xx/(10(x-2)*5(x+3))*5), so:

-110xx/(10(x-2)*5(x+3))*5

We multiply all the terms by the denominator


-110xx

Back to the equation:

+(-110xx)





We calculate terms in parentheses: +(60xx/(10(x-2)*5(x+3))*5), so:

60xx/(10(x-2)*5(x+3))*5

We multiply all the terms by the denominator


60xx

Back to the equation:

+(60xx)



We get rid of parentheses

225xx-110xx+60xx=0

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