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6/5x+2/3x=28
We move all terms to the left:
6/5x+2/3x-(28)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
18x/15x^2+10x/15x^2-28=0
We multiply all the terms by the denominator
18x+10x-28*15x^2=0
We add all the numbers together, and all the variables
28x-28*15x^2=0
Wy multiply elements
-420x^2+28x=0
a = -420; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-420)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-420}=\frac{-56}{-840} =1/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-420}=\frac{0}{-840} =0 $
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