6/3x-1=9/5x-3

Solution for 6/3x-1=9/5x-3 equation:

6/3x-1=9/5x-3

We move all terms to the left:

6/3x-1-(9/5x-3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 5x-3)!=0

x∈R


We get rid of parentheses

6/3x-9/5x+3-1=0

We calculate fractions


30x/15x^2+(-27x)/15x^2+3-1=0

We add all the numbers together, and all the variables

30x/15x^2+(-27x)/15x^2+2=0

We multiply all the terms by the denominator


30x+(-27x)+2*15x^2=0

Wy multiply elements

30x^2+30x+(-27x)=0

We get rid of parentheses

30x^2+30x-27x=0

We add all the numbers together, and all the variables

30x^2+3x=0

a = 30; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·30·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*30}=\frac{-6}{60}
=-1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*30}=\frac{0}{60}
=0
$