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6/3x+5/6x=36/9
We move all terms to the left:
6/3x+5/6x-(36/9)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
6/3x+5/6x-4=0
We calculate fractions
36x/18x^2+15x/18x^2-4=0
We multiply all the terms by the denominator
36x+15x-4*18x^2=0
We add all the numbers together, and all the variables
51x-4*18x^2=0
Wy multiply elements
-72x^2+51x=0
a = -72; b = 51; c = 0;
Δ = b2-4ac
Δ = 512-4·(-72)·0
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-51}{2*-72}=\frac{-102}{-144} =17/24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+51}{2*-72}=\frac{0}{-144} =0 $
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