6/2-3/3x=3/x+3/3

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Solution for 6/2-3/3x=3/x+3/3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

6/2-((3/3)*x) = 3/x+3/3 // - 3/x+3/3

6/2-((3/3)*x)-(3/x)-(3/3) = 0

6/2-x-3*x^-1-1 = 0

2*x^0-1*x^1-3*x^-1 = 0

(2*x^1-1*x^2-3*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^1-1*x^2-3*x^0) = 0

x^1

2*x-x^2-3 = 0

2*x-x^2-3 = 0

DELTA = 2^2-(-3*(-1)*4)

DELTA = -8

DELTA < 0

x in { } 

x belongs to the empty set

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