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6/(x(x+3))+7/(2(x+3))=8/x
We move all terms to the left:
6/(x(x+3))+7/(2(x+3))-(8/x)=0
Domain of the equation: (x(x+3))!=0
x∈R
Domain of the equation: (2(x+3))!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
6/(x(x+3))+7/(2(x+3))-(+8/x)=0
We get rid of parentheses
6/(x(x+3))+7/(2(x+3))-8/x=0
We calculate fractions
(6*(2(x+3))*x)/((x(x+3))*(2(x+3))*x)+(7*(x(x+3))*x)/((x(x+3))*(2(x+3))*x)+(-8*(x(x+3))*(2(x+3)))/((x(x+3))*(2(x+3))*x)=0
We calculate terms in parentheses: +(6*(2(x+3))*x)/((x(x+3))*(2(x+3))*x), so:
6*(2(x+3))*x)/((x(x+3))*(2(x+3))*x
We multiply all the terms by the denominator
6*(2(x+3))*x)
Back to the equation:
+(6*(2(x+3))*x))
We calculate terms in parentheses: +(7*(x(x+3))*x)/((x(x+3))*(2(x+3))*x), so:
7*(x(x+3))*x)/((x(x+3))*(2(x+3))*x
We multiply all the terms by the denominator
7*(x(x+3))*x)
Back to the equation:
+(7*(x(x+3))*x))
We calculate terms in parentheses: +(-8*(x(x+3))*(2(x+3)))/((x(x+3))*(2(x+3))*x), so:
-8*(x(x+3))*(2(x+3)))/((x(x+3))*(2(x+3))*x
We multiply all the terms by the denominator
-8*(x(x+3))*(2(x+3)))
Back to the equation:
+(-8*(x(x+3))*(2(x+3))))
We calculate terms in parentheses: +(6*(2(x+3))*x))+(7*(x(x+3))*x))+(-8*(x(x+3))*(2(x+3)))), so:
6*(2(x+3))*x))+(7*(x(x+3))*x))+(-8*(x(x+3))*(2(x+3)))
We add all the numbers together, and all the variables
6*(2(x+3))*x))+(7*(x(x+3))*x))+(-8*(x(x+3))*(2(x
Back to the equation:
+(6*(2(x+3))*x))+(7*(x(x+3))*x))+(-8*(x(x+3))*(2(x)
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