6/(f+2)=2/(f-1)

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Solution for 6/(f+2)=2/(f-1) equation: 



6/(f+2)=2/(f-1)

We move all terms to the left:

6/(f+2)-(2/(f-1))=0



Domain of the equation: (f+2)!=0

We move all terms containing f to the left, all other terms to the right

f!=-2

f∈R





Domain of the equation: (f-1))!=0

f∈R



We calculate fractions


6f/((f+2)*(f-1)))+(-(2*(f+2))/((f+2)*(f-1)))=0



We calculate terms in parentheses: -(2*(f+2))/((f+2)*(f-1))), so:

2*(f+2))/((f+2)*(f-1))

We multiply all the terms by the denominator


2*(f+2))

We multiply parentheses

2f+

We add all the numbers together, and all the variables

2f

Back to the equation:

-(2f)



We add all the numbers together, and all the variables

-2f+6f/((f+2)*(f-1)))+(=0

We multiply all the terms by the denominator


-2f*((f+2)*(f-1)))+(+6f=0

We add all the numbers together, and all the variables

6f-2f*((f+2)*(f-1)))+(=0

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