6/(7/(8x)+8)

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Solution for 6/(7/(8x)+8) equation: 


D( x )

7/(8*x)+8 = 0

8*x = 0

7/(8*x)+8 = 0

7/(8*x)+8 = 0

7/8*x^-1 = -8 // : 7/8

x^-1 = -64/7

-1 < 0

1/(x^1) = -64/7 // * x^1

1 = -64/7*x^1 // : -64/7

-7/64 = x^1

x = -7/64

8*x = 0

8*x = 0

8*x = 0 // : 8

x = 0

x in (-oo:-7/64) U (-7/64:0) U (0:+oo)

6/(7/(8*x)+8) = 0

6/(7/8*x^-1+8) = 0

x belongs to the empty set

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