6/(2x-pi)

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Solution for 6/(2x-pi) equation: 


D( x )

2*x-pi = 0

2*x-pi = 0

2*x-pi = 0

2*x-pi = 0 // + pi

2*x = pi // : 2

x = pi/2

x in (-oo:pi/2) U (pi/2:+oo)

6/(2*x-pi) = 0

x belongs to the empty set

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