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6/(2x-1)=4/(x+1)
We move all terms to the left:
6/(2x-1)-(4/(x+1))=0
Domain of the equation: (2x-1)!=0
We move all terms containing x to the left, all other terms to the right
2x!=1
x!=1/2
x!=1/2
x∈R
Domain of the equation: (x+1))!=0We calculate fractions
x∈R
6x/((2x-1)*(x+1)))+(-(4*(2x-1))/((2x-1)*(x+1)))=0
We calculate terms in parentheses: -(4*(2x-1))/((2x-1)*(x+1))), so:We add all the numbers together, and all the variables
4*(2x-1))/((2x-1)*(x+1))
We multiply all the terms by the denominator
4*(2x-1))
We multiply parentheses
8x+
We add all the numbers together, and all the variables
8x
Back to the equation:
-(8x)
-8x+6x/((2x-1)*(x+1)))+(=0
We multiply all the terms by the denominator
-8x*((2x-1)*(x+1)))+(+6x=0
We add all the numbers together, and all the variables
6x-8x*((2x-1)*(x+1)))+(=0
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