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6.25=2x^2+2
We move all terms to the left:
6.25-(2x^2+2)=0
We get rid of parentheses
-2x^2-2+6.25=0
We add all the numbers together, and all the variables
-2x^2+4.25=0
a = -2; b = 0; c = +4.25;
Δ = b2-4ac
Δ = 02-4·(-2)·4.25
Δ = 34
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{34}}{2*-2}=\frac{0-\sqrt{34}}{-4} =-\frac{\sqrt{}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{34}}{2*-2}=\frac{0+\sqrt{34}}{-4} =\frac{\sqrt{}}{-4} $
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