6-x+6(1-x)+6(2-x)+6(3-x)=259

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Solution for 6-x+6(1-x)+6(2-x)+6(3-x)=259 equation: 



6-x+6(1-x)+6(2-x)+6(3-x)=259

We move all terms to the left:

6-x+6(1-x)+6(2-x)+6(3-x)-(259)=0

We add all the numbers together, and all the variables

-x+6(-1x+1)+6(-1x+2)+6(-1x+3)+6-259=0

We add all the numbers together, and all the variables

-1x+6(-1x+1)+6(-1x+2)+6(-1x+3)-253=0

We multiply parentheses

-1x-6x-6x-6x+6+12+18-253=0

We add all the numbers together, and all the variables

-19x-217=0

We move all terms containing x to the left, all other terms to the right

-19x=217

x=217/-19

x=-11+8/19

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