6-5x+2x2=4+2x(x-6)

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Solution for 6-5x+2x2=4+2x(x-6) equation: 



6-5x+2x^2=4+2x(x-6)

We move all terms to the left:

6-5x+2x^2-(4+2x(x-6))=0



We calculate terms in parentheses: -(4+2x(x-6)), so:

4+2x(x-6)

determiningTheFunctionDomain
2x(x-6)+4

We multiply parentheses

2x^2-12x+4

Back to the equation:

-(2x^2-12x+4)



We get rid of parentheses

2x^2-2x^2-5x+12x-4+6=0

We add all the numbers together, and all the variables

7x+2=0

We move all terms containing x to the left, all other terms to the right

7x=-2

x=-2/7

x=-2/7

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