6-4(y+3)=2(y+2)

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Solution for 6-4(y+3)=2(y+2) equation: 



6-4(y+3)=2(y+2)

We move all terms to the left:

6-4(y+3)-(2(y+2))=0

We multiply parentheses

-4y-(2(y+2))-12+6=0



We calculate terms in parentheses: -(2(y+2)), so:

2(y+2)

We multiply parentheses

2y+4

Back to the equation:

-(2y+4)



We add all the numbers together, and all the variables

-4y-(2y+4)-6=0

We get rid of parentheses

-4y-2y-4-6=0

We add all the numbers together, and all the variables

-6y-10=0

We move all terms containing y to the left, all other terms to the right

-6y=10

y=10/-6

y=-1+2/3

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