6-4(1+2b)=42

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Solution for 6-4(1+2b)=42 equation: 



6-4(1+2b)=42

We move all terms to the left:

6-4(1+2b)-(42)=0

We add all the numbers together, and all the variables

-4(2b+1)+6-42=0

We add all the numbers together, and all the variables

-4(2b+1)-36=0

We multiply parentheses

-8b-4-36=0

We add all the numbers together, and all the variables

-8b-40=0

We move all terms containing b to the left, all other terms to the right

-8b=40

b=40/-8

b=-5

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