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6-3x=3(2-x)
We move all terms to the left:
6-3x-(3(2-x))=0
We add all the numbers together, and all the variables
-3x-(3(-1x+2))+6=0
We calculate terms in parentheses: -(3(-1x+2)), so:We get rid of parentheses
3(-1x+2)
We multiply parentheses
-3x+6
Back to the equation:
-(-3x+6)
-3x+3x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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