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6-3c=2(c-2)
We move all terms to the left:
6-3c-(2(c-2))=0
We calculate terms in parentheses: -(2(c-2)), so:We get rid of parentheses
2(c-2)
We multiply parentheses
2c-4
Back to the equation:
-(2c-4)
-3c-2c+4+6=0
We add all the numbers together, and all the variables
-5c+10=0
We move all terms containing c to the left, all other terms to the right
-5c=-10
c=-10/-5
c=+2
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