6-3c+6c=3(4c-1)

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Solution for 6-3c+6c=3(4c-1) equation: 



6-3c+6c=3(4c-1)

We move all terms to the left:

6-3c+6c-(3(4c-1))=0

We add all the numbers together, and all the variables

3c-(3(4c-1))+6=0



We calculate terms in parentheses: -(3(4c-1)), so:

3(4c-1)

We multiply parentheses

12c-3

Back to the equation:

-(12c-3)



We get rid of parentheses

3c-12c+3+6=0

We add all the numbers together, and all the variables

-9c+9=0

We move all terms containing c to the left, all other terms to the right

-9c=-9

c=-9/-9

c=1

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