6-3(4p+1)=5(p+4)

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Solution for 6-3(4p+1)=5(p+4) equation: 



6-3(4p+1)=5(p+4)

We move all terms to the left:

6-3(4p+1)-(5(p+4))=0

We multiply parentheses

-12p-(5(p+4))-3+6=0



We calculate terms in parentheses: -(5(p+4)), so:

5(p+4)

We multiply parentheses

5p+20

Back to the equation:

-(5p+20)



We add all the numbers together, and all the variables

-12p-(5p+20)+3=0

We get rid of parentheses

-12p-5p-20+3=0

We add all the numbers together, and all the variables

-17p-17=0

We move all terms containing p to the left, all other terms to the right

-17p=17

p=17/-17

p=-1

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