6-2y+4=8y-10(y-1)

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Solution for 6-2y+4=8y-10(y-1) equation: 



6-2y+4=8y-10(y-1)

We move all terms to the left:

6-2y+4-(8y-10(y-1))=0

We add all the numbers together, and all the variables

-2y-(8y-10(y-1))+10=0



We calculate terms in parentheses: -(8y-10(y-1)), so:

8y-10(y-1)

We multiply parentheses

8y-10y+10

We add all the numbers together, and all the variables

-2y+10

Back to the equation:

-(-2y+10)



We get rid of parentheses

-2y+2y-10+10=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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