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6-2x=2(3-x)
We move all terms to the left:
6-2x-(2(3-x))=0
We add all the numbers together, and all the variables
-2x-(2(-1x+3))+6=0
We calculate terms in parentheses: -(2(-1x+3)), so:We get rid of parentheses
2(-1x+3)
We multiply parentheses
-2x+6
Back to the equation:
-(-2x+6)
-2x+2x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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