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6-2(x+4)=7-3(x+3)
We move all terms to the left:
6-2(x+4)-(7-3(x+3))=0
We multiply parentheses
-2x-(7-3(x+3))-8+6=0
We calculate terms in parentheses: -(7-3(x+3)), so:We add all the numbers together, and all the variables
7-3(x+3)
determiningTheFunctionDomain -3(x+3)+7
We multiply parentheses
-3x-9+7
We add all the numbers together, and all the variables
-3x-2
Back to the equation:
-(-3x-2)
-2x-(-3x-2)-2=0
We get rid of parentheses
-2x+3x+2-2=0
We add all the numbers together, and all the variables
x=0
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