6-2(x+4)=7(3x-1)+28

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Solution for 6-2(x+4)=7(3x-1)+28 equation:



6-2(x+4)=7(3x-1)+28
We move all terms to the left:
6-2(x+4)-(7(3x-1)+28)=0
We multiply parentheses
-2x-(7(3x-1)+28)-8+6=0
We calculate terms in parentheses: -(7(3x-1)+28), so:
7(3x-1)+28
We multiply parentheses
21x-7+28
We add all the numbers together, and all the variables
21x+21
Back to the equation:
-(21x+21)
We add all the numbers together, and all the variables
-2x-(21x+21)-2=0
We get rid of parentheses
-2x-21x-21-2=0
We add all the numbers together, and all the variables
-23x-23=0
We move all terms containing x to the left, all other terms to the right
-23x=23
x=23/-23
x=-1

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