6-2(b+3)+1=2b-4(b+5)

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Solution for 6-2(b+3)+1=2b-4(b+5) equation:


Simplifying
6 + -2(b + 3) + 1 = 2b + -4(b + 5)

Reorder the terms:
6 + -2(3 + b) + 1 = 2b + -4(b + 5)
6 + (3 * -2 + b * -2) + 1 = 2b + -4(b + 5)
6 + (-6 + -2b) + 1 = 2b + -4(b + 5)

Reorder the terms:
6 + -6 + 1 + -2b = 2b + -4(b + 5)

Combine like terms: 6 + -6 = 0
0 + 1 + -2b = 2b + -4(b + 5)
1 + -2b = 2b + -4(b + 5)

Reorder the terms:
1 + -2b = 2b + -4(5 + b)
1 + -2b = 2b + (5 * -4 + b * -4)
1 + -2b = 2b + (-20 + -4b)

Reorder the terms:
1 + -2b = -20 + 2b + -4b

Combine like terms: 2b + -4b = -2b
1 + -2b = -20 + -2b

Add '2b' to each side of the equation.
1 + -2b + 2b = -20 + -2b + 2b

Combine like terms: -2b + 2b = 0
1 + 0 = -20 + -2b + 2b
1 = -20 + -2b + 2b

Combine like terms: -2b + 2b = 0
1 = -20 + 0
1 = -20

Solving
1 = -20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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