6-2(4+3x)=3(x-2)

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Solution for 6-2(4+3x)=3(x-2) equation: 



6-2(4+3x)=3(x-2)

We move all terms to the left:

6-2(4+3x)-(3(x-2))=0

We add all the numbers together, and all the variables

-2(3x+4)-(3(x-2))+6=0

We multiply parentheses

-6x-(3(x-2))-8+6=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

-6x-(3x-6)-2=0

We get rid of parentheses

-6x-3x+6-2=0

We add all the numbers together, and all the variables

-9x+4=0

We move all terms containing x to the left, all other terms to the right

-9x=-4

x=-4/-9

x=4/9

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