6-2(3y+1)-7y=-2y+4(2-1)+3

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Solution for 6-2(3y+1)-7y=-2y+4(2-1)+3 equation: 



6-2(3y+1)-7y=-2y+4(2-1)+3

We move all terms to the left:

6-2(3y+1)-7y-(-2y+4(2-1)+3)=0

We add all the numbers together, and all the variables

-2(3y+1)-7y-(-2y+41+3)+6=0

We add all the numbers together, and all the variables

-7y-2(3y+1)-(-2y+41+3)+6=0

We multiply parentheses

-7y-6y-(-2y+41+3)-2+6=0

We get rid of parentheses

-7y-6y+2y-41-3-2+6=0

We add all the numbers together, and all the variables

-11y-40=0

We move all terms containing y to the left, all other terms to the right

-11y=40

y=40/-11

y=-3+7/11

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