6-2(3x+1)=4(2x+3)-(5x-2)

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Solution for 6-2(3x+1)=4(2x+3)-(5x-2) equation: 



6-2(3x+1)=4(2x+3)-(5x-2)

We move all terms to the left:

6-2(3x+1)-(4(2x+3)-(5x-2))=0

We multiply parentheses

-6x-(4(2x+3)-(5x-2))-2+6=0



We calculate terms in parentheses: -(4(2x+3)-(5x-2)), so:

4(2x+3)-(5x-2)

We multiply parentheses

8x-(5x-2)+12

We get rid of parentheses

8x-5x+2+12

We add all the numbers together, and all the variables

3x+14

Back to the equation:

-(3x+14)



We add all the numbers together, and all the variables

-6x-(3x+14)+4=0

We get rid of parentheses

-6x-3x-14+4=0

We add all the numbers together, and all the variables

-9x-10=0

We move all terms containing x to the left, all other terms to the right

-9x=10

x=10/-9

x=-1+1/9

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