6-2(3x+1)=4(2x+)-(5x-2)

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Solution for 6-2(3x+1)=4(2x+)-(5x-2) equation: 



6-2(3x+1)=4(2x+)-(5x-2)

We move all terms to the left:

6-2(3x+1)-(4(2x+)-(5x-2))=0

We add all the numbers together, and all the variables

-2(3x+1)-(4(+2x)-(5x-2))+6=0

We multiply parentheses

-6x-(4(+2x)-(5x-2))-2+6=0



We calculate terms in parentheses: -(4(+2x)-(5x-2)), so:

4(+2x)-(5x-2)

We multiply parentheses

8x-(5x-2)

We get rid of parentheses

8x-5x+2

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We add all the numbers together, and all the variables

-6x-(3x+2)+4=0

We get rid of parentheses

-6x-3x-2+4=0

We add all the numbers together, and all the variables

-9x+2=0

We move all terms containing x to the left, all other terms to the right

-9x=-2

x=-2/-9

x=2/9

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