6-2(-6z+5)=2z+8

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Solution for 6-2(-6z+5)=2z+8 equation: 



6-2(-6z+5)=2z+8

We move all terms to the left:

6-2(-6z+5)-(2z+8)=0

We multiply parentheses

12z-(2z+8)-10+6=0

We get rid of parentheses

12z-2z-8-10+6=0

We add all the numbers together, and all the variables

10z-12=0

We move all terms containing z to the left, all other terms to the right

10z=12

z=12/10

z=1+1/5

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