6-(3x+10)+4(2-x)=14

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Solution for 6-(3x+10)+4(2-x)=14 equation: 



6-(3x+10)+4(2-x)=14

We move all terms to the left:

6-(3x+10)+4(2-x)-(14)=0

We add all the numbers together, and all the variables

-(3x+10)+4(-1x+2)+6-14=0

We add all the numbers together, and all the variables

-(3x+10)+4(-1x+2)-8=0

We multiply parentheses

-(3x+10)-4x+8-8=0

We get rid of parentheses

-3x-4x-10+8-8=0

We add all the numbers together, and all the variables

-7x-10=0

We move all terms containing x to the left, all other terms to the right

-7x=10

x=10/-7

x=-1+3/7

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