6-(2+3x)-31=7x-3(2x-5)

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Solution for 6-(2+3x)-31=7x-3(2x-5) equation: 



6-(2+3x)-31=7x-3(2x-5)

We move all terms to the left:

6-(2+3x)-31-(7x-3(2x-5))=0

We add all the numbers together, and all the variables

-(3x+2)-(7x-3(2x-5))+6-31=0

We add all the numbers together, and all the variables

-(3x+2)-(7x-3(2x-5))-25=0

We get rid of parentheses

-3x-(7x-3(2x-5))-2-25=0



We calculate terms in parentheses: -(7x-3(2x-5)), so:

7x-3(2x-5)

We multiply parentheses

7x-6x+15

We add all the numbers together, and all the variables

x+15

Back to the equation:

-(x+15)



We add all the numbers together, and all the variables

-3x-(x+15)-27=0

We get rid of parentheses

-3x-x-15-27=0

We add all the numbers together, and all the variables

-4x-42=0

We move all terms containing x to the left, all other terms to the right

-4x=42

x=42/-4

x=-10+1/2

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