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6+7(x-5)=5+3(2x-2)
We move all terms to the left:
6+7(x-5)-(5+3(2x-2))=0
We multiply parentheses
7x-(5+3(2x-2))-35+6=0
We calculate terms in parentheses: -(5+3(2x-2)), so:We add all the numbers together, and all the variables
5+3(2x-2)
determiningTheFunctionDomain 3(2x-2)+5
We multiply parentheses
6x-6+5
We add all the numbers together, and all the variables
6x-1
Back to the equation:
-(6x-1)
7x-(6x-1)-29=0
We get rid of parentheses
7x-6x+1-29=0
We add all the numbers together, and all the variables
x-28=0
We move all terms containing x to the left, all other terms to the right
x=28
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