6+6(r+6)=4(3+8r)+4r

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Solution for 6+6(r+6)=4(3+8r)+4r equation: 



6+6(r+6)=4(3+8r)+4r

We move all terms to the left:

6+6(r+6)-(4(3+8r)+4r)=0

We add all the numbers together, and all the variables

6(r+6)-(4(8r+3)+4r)+6=0

We multiply parentheses

6r-(4(8r+3)+4r)+36+6=0



We calculate terms in parentheses: -(4(8r+3)+4r), so:

4(8r+3)+4r

We add all the numbers together, and all the variables

4r+4(8r+3)

We multiply parentheses

4r+32r+12

We add all the numbers together, and all the variables

36r+12

Back to the equation:

-(36r+12)



We add all the numbers together, and all the variables

6r-(36r+12)+42=0

We get rid of parentheses

6r-36r-12+42=0

We add all the numbers together, and all the variables

-30r+30=0

We move all terms containing r to the left, all other terms to the right

-30r=-30

r=-30/-30

r=1

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