6+6(1+3v)=8-8(1-3v)

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Solution for 6+6(1+3v)=8-8(1-3v) equation: 



6+6(1+3v)=8-8(1-3v)

We move all terms to the left:

6+6(1+3v)-(8-8(1-3v))=0

We add all the numbers together, and all the variables

6(3v+1)-(8-8(-3v+1))+6=0

We multiply parentheses

18v-(8-8(-3v+1))+6+6=0



We calculate terms in parentheses: -(8-8(-3v+1)), so:

8-8(-3v+1)

determiningTheFunctionDomain
-8(-3v+1)+8

We multiply parentheses

24v-8+8

We add all the numbers together, and all the variables

24v

Back to the equation:

-(24v)



We add all the numbers together, and all the variables

-6v+12=0

We move all terms containing v to the left, all other terms to the right

-6v=-12

v=-12/-6

v=+2

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