6+5(2x+1)=3(9x+10)+-376

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Solution for 6+5(2x+1)=3(9x+10)+-376 equation: 



6+5(2x+1)=3(9x+10)+-376

We move all terms to the left:

6+5(2x+1)-(3(9x+10)+-376)=0

We use the square of the difference formula

5(2x+1)-(3(9x+10)-376)+6=0

We multiply parentheses

10x-(3(9x+10)-376)+5+6=0



We calculate terms in parentheses: -(3(9x+10)-376), so:

3(9x+10)-376

We multiply parentheses

27x+30-376

We add all the numbers together, and all the variables

27x-346

Back to the equation:

-(27x-346)



We add all the numbers together, and all the variables

10x-(27x-346)+11=0

We get rid of parentheses

10x-27x+346+11=0

We add all the numbers together, and all the variables

-17x+357=0

We move all terms containing x to the left, all other terms to the right

-17x=-357

x=-357/-17

x=+21

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