6+4x-3=(x-4)+8

Solution for 6+4x-3=(x-4)+8 equation:

6+4x-3=(x-4)+8

We move all terms to the left:

6+4x-3-((x-4)+8)=0

We add all the numbers together, and all the variables

4x-((x-4)+8)+3=0


We calculate terms in parentheses: -((x-4)+8), so:

(x-4)+8

We get rid of parentheses

x-4+8

We add all the numbers together, and all the variables

x+4

Back to the equation:

-(x+4)


We get rid of parentheses

4x-x-4+3=0

We add all the numbers together, and all the variables

3x-1=0

We move all terms containing x to the left, all other terms to the right

3x=1

x=1/3

x=1/3