6+4v+7v=3(6v-12)-4(v-6)

Solution for 6+4v+7v=3(6v-12)-4(v-6) equation:

6+4v+7v=3(6v-12)-4(v-6)

We move all terms to the left:

6+4v+7v-(3(6v-12)-4(v-6))=0

We add all the numbers together, and all the variables

11v-(3(6v-12)-4(v-6))+6=0


We calculate terms in parentheses: -(3(6v-12)-4(v-6)), so:

3(6v-12)-4(v-6)

We multiply parentheses

18v-4v-36+24

We add all the numbers together, and all the variables

14v-12

Back to the equation:

-(14v-12)


We get rid of parentheses

11v-14v+12+6=0

We add all the numbers together, and all the variables

-3v+18=0

We move all terms containing v to the left, all other terms to the right

-3v=-18

v=-18/-3

v=+6