6+4p=2(p-3)-2(p-2)

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Solution for 6+4p=2(p-3)-2(p-2) equation: 



6+4p=2(p-3)-2(p-2)

We move all terms to the left:

6+4p-(2(p-3)-2(p-2))=0



We calculate terms in parentheses: -(2(p-3)-2(p-2)), so:

2(p-3)-2(p-2)

We multiply parentheses

2p-2p-6+4

We add all the numbers together, and all the variables

-2

Back to the equation:

-(-2)



We add all the numbers together, and all the variables

4p+8=0

We move all terms containing p to the left, all other terms to the right

4p=-8

p=-8/4

p=-2

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