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6+4/5p=9/10p
We move all terms to the left:
6+4/5p-(9/10p)=0
Domain of the equation: 5p!=0
p!=0/5
p!=0
p∈R
Domain of the equation: 10p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
4/5p-(+9/10p)+6=0
We get rid of parentheses
4/5p-9/10p+6=0
We calculate fractions
40p/50p^2+(-45p)/50p^2+6=0
We multiply all the terms by the denominator
40p+(-45p)+6*50p^2=0
Wy multiply elements
300p^2+40p+(-45p)=0
We get rid of parentheses
300p^2+40p-45p=0
We add all the numbers together, and all the variables
300p^2-5p=0
a = 300; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·300·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*300}=\frac{0}{600} =0 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*300}=\frac{10}{600} =1/60 $
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