6+4(2v-1)=-2(3v-9)+8v

Solution for 6+4(2v-1)=-2(3v-9)+8v equation:

6+4(2v-1)=-2(3v-9)+8v

We move all terms to the left:

6+4(2v-1)-(-2(3v-9)+8v)=0

We multiply parentheses

8v-(-2(3v-9)+8v)-4+6=0


We calculate terms in parentheses: -(-2(3v-9)+8v), so:

-2(3v-9)+8v

We add all the numbers together, and all the variables

8v-2(3v-9)

We multiply parentheses

8v-6v+18

We add all the numbers together, and all the variables

2v+18

Back to the equation:

-(2v+18)


We add all the numbers together, and all the variables

8v-(2v+18)+2=0

We get rid of parentheses

8v-2v-18+2=0

We add all the numbers together, and all the variables

6v-16=0

We move all terms containing v to the left, all other terms to the right

6v=16

v=16/6

v=2+2/3