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6+3x/2x=2x/6
We move all terms to the left:
6+3x/2x-(2x/6)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3x/2x-(+2x/6)+6=0
We get rid of parentheses
3x/2x-2x/6+6=0
We calculate fractions
(-4x^2)/12x+18x/12x+6=0
We multiply all the terms by the denominator
(-4x^2)+18x+6*12x=0
Wy multiply elements
(-4x^2)+18x+72x=0
We get rid of parentheses
-4x^2+18x+72x=0
We add all the numbers together, and all the variables
-4x^2+90x=0
a = -4; b = 90; c = 0;
Δ = b2-4ac
Δ = 902-4·(-4)·0
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-90}{2*-4}=\frac{-180}{-8} =22+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+90}{2*-4}=\frac{0}{-8} =0 $
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