6+3x-8=2(x-4)+2x

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Solution for 6+3x-8=2(x-4)+2x equation: 



6+3x-8=2(x-4)+2x

We move all terms to the left:

6+3x-8-(2(x-4)+2x)=0

We add all the numbers together, and all the variables

3x-(2(x-4)+2x)-2=0



We calculate terms in parentheses: -(2(x-4)+2x), so:

2(x-4)+2x

We add all the numbers together, and all the variables

2x+2(x-4)

We multiply parentheses

2x+2x-8

We add all the numbers together, and all the variables

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

3x-4x+8-2=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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