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6+3/2x=x-2
We move all terms to the left:
6+3/2x-(x-2)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
3/2x-x+2+6=0
We multiply all the terms by the denominator
-x*2x+2*2x+6*2x+3=0
Wy multiply elements
-2x^2+4x+12x+3=0
We add all the numbers together, and all the variables
-2x^2+16x+3=0
a = -2; b = 16; c = +3;
Δ = b2-4ac
Δ = 162-4·(-2)·3
Δ = 280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{280}=\sqrt{4*70}=\sqrt{4}*\sqrt{70}=2\sqrt{70}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{70}}{2*-2}=\frac{-16-2\sqrt{70}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{70}}{2*-2}=\frac{-16+2\sqrt{70}}{-4} $
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