6+3/2x=7/4x+5

Solution for 6+3/2x=7/4x+5 equation:

6+3/2x=7/4x+5

We move all terms to the left:

6+3/2x-(7/4x+5)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 4x+5)!=0

x∈R


We get rid of parentheses

3/2x-7/4x-5+6=0

We calculate fractions


12x/8x^2+(-14x)/8x^2-5+6=0

We add all the numbers together, and all the variables

12x/8x^2+(-14x)/8x^2+1=0

We multiply all the terms by the denominator


12x+(-14x)+1*8x^2=0

Wy multiply elements

8x^2+12x+(-14x)=0

We get rid of parentheses

8x^2+12x-14x=0

We add all the numbers together, and all the variables

8x^2-2x=0

a = 8; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·8·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*8}=\frac{0}{16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*8}=\frac{4}{16}
=1/4
$