6+3(5x-4)=5-4(2x+1)

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Solution for 6+3(5x-4)=5-4(2x+1) equation: 



6+3(5x-4)=5-4(2x+1)

We move all terms to the left:

6+3(5x-4)-(5-4(2x+1))=0

We multiply parentheses

15x-(5-4(2x+1))-12+6=0



We calculate terms in parentheses: -(5-4(2x+1)), so:

5-4(2x+1)

determiningTheFunctionDomain
-4(2x+1)+5

We multiply parentheses

-8x-4+5

We add all the numbers together, and all the variables

-8x+1

Back to the equation:

-(-8x+1)



We add all the numbers together, and all the variables

15x-(-8x+1)-6=0

We get rid of parentheses

15x+8x-1-6=0

We add all the numbers together, and all the variables

23x-7=0

We move all terms containing x to the left, all other terms to the right

23x=7

x=7/23

x=7/23

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