6+2k=2(3+k)

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Solution for 6+2k=2(3+k) equation: 



6+2k=2(3+k)

We move all terms to the left:

6+2k-(2(3+k))=0

We add all the numbers together, and all the variables

2k-(2(k+3))+6=0



We calculate terms in parentheses: -(2(k+3)), so:

2(k+3)

We multiply parentheses

2k+6

Back to the equation:

-(2k+6)



We get rid of parentheses

2k-2k-6+6=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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