6+2c=3(c-1)

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Solution for 6+2c=3(c-1) equation: 



6+2c=3(c-1)

We move all terms to the left:

6+2c-(3(c-1))=0



We calculate terms in parentheses: -(3(c-1)), so:

3(c-1)

We multiply parentheses

3c-3

Back to the equation:

-(3c-3)



We get rid of parentheses

2c-3c+3+6=0

We add all the numbers together, and all the variables

-1c+9=0

We move all terms containing c to the left, all other terms to the right

-c=-9

c=-9/-1

c=+9

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