6+2/5b=20

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Solution for 6+2/5b=20 equation: 



6+2/5b=20

We move all terms to the left:

6+2/5b-(20)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We add all the numbers together, and all the variables

2/5b-14=0

We multiply all the terms by the denominator


-14*5b+2=0

Wy multiply elements

-70b+2=0

We move all terms containing b to the left, all other terms to the right

-70b=-2

b=-2/-70

b=1/35

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