6+2(7u-5)=-2(2u-1)+3u

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Solution for 6+2(7u-5)=-2(2u-1)+3u equation: 



6+2(7u-5)=-2(2u-1)+3u

We move all terms to the left:

6+2(7u-5)-(-2(2u-1)+3u)=0

We multiply parentheses

14u-(-2(2u-1)+3u)-10+6=0



We calculate terms in parentheses: -(-2(2u-1)+3u), so:

-2(2u-1)+3u

We add all the numbers together, and all the variables

3u-2(2u-1)

We multiply parentheses

3u-4u+2

We add all the numbers together, and all the variables

-1u+2

Back to the equation:

-(-1u+2)



We add all the numbers together, and all the variables

14u-(-1u+2)-4=0

We get rid of parentheses

14u+1u-2-4=0

We add all the numbers together, and all the variables

15u-6=0

We move all terms containing u to the left, all other terms to the right

15u=6

u=6/15

u=2/5

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