6+2(4x-2)=-2(3x-3)+6x

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Solution for 6+2(4x-2)=-2(3x-3)+6x equation: 



6+2(4x-2)=-2(3x-3)+6x

We move all terms to the left:

6+2(4x-2)-(-2(3x-3)+6x)=0

We multiply parentheses

8x-(-2(3x-3)+6x)-4+6=0



We calculate terms in parentheses: -(-2(3x-3)+6x), so:

-2(3x-3)+6x

We add all the numbers together, and all the variables

6x-2(3x-3)

We multiply parentheses

6x-6x+6

We add all the numbers together, and all the variables

6

Back to the equation:

-(6)



We add all the numbers together, and all the variables

8x-4=0

We move all terms containing x to the left, all other terms to the right

8x=4

x=4/8

x=1/2

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